Question

Problem 2: Python 3

Implement a function called gee_whiz that does the following: given argument n, a positive integer, it returns a list of n tuples corresponding to the numbers 1 through n (both inclusive): the tuple for the number k consists of k as the first component, and exactly one of the following strings as the second:

• the string 'two!' if k is divisible by 2
• the string 'three!' if k is divisible by 3
• the string 'five!' if k is divisible by 5
• the string 'two!three!' if k is divisible by 2 and 3
• the string 'three!five!' if k is divisible by 3 and 5
• the string 'two!five!' if k is divisible by 2 and 5
• the string 'two!three!five' if k is divisible by 2, 3 and 5 • the empty string otherwise

The most specific condition applies, e.g. if k is 12, the corresponding string is “two!three!”. For example, the function call

gee_whiz(30) returns the list of 30 tuples (not all shown) below:

Hint: You should be able to do this with fewer than 8 conditions inside the loop. Do not modify the doctests.

def gee_whiz(n):
"""Returns list of n tuples of the form (k, <string_k>)

Args:
n (int >=0)

>>> gee_whiz(6)
[(1, ''), (2, 'two!'), (3, 'three!'), (4, 'two!'), (5, 'five!'), (6, 'two!three!')]
>>> a = gee_whiz(20)
>>> a[14]
(15, 'three!five!')
"""
#code here

Answer 1

Python code:

#initializing gee_whiz function
def gee_whiz(n):
    #initializing list to store tuples
    lis=[]
    #looping from 1 to n(inclusive)
    for i in range(1,n+1):
        #checking if number is divisible by 2,3,5
        if(i%2==0 and i%3==0 and i%5==0):
            #adding to lis, tuple for divisible by 2,3,5
            lis.append((i,'two!three!five'))
        #checking if number is divisible by 2,5
        elif(i%2==0 and i%5==0):
            #adding to lis, tuple for divisible by 2,5
            lis.append((i,'two!five!'))
        #checking if number is divisible by 3,5
        elif(i%3==0 and i%5==0):
            #adding to lis, tuple for divisible by 3,5
            lis.append((i,'three!five!'))
        #checking if number is divisible by 2,3
        elif(i%2==0 and i%3==0):
            #adding to lis, tuple for divisible by 2,3
            lis.append((i,'two!three!'))
        #checking if number is divisible by 2
        elif(i%2==0):
            #adding to lis, tuple for divisible by 2
            lis.append((i,'two!'))
        #checking if number is divisible by 3
        elif(i%3==0):
            #adding to lis, tuple for divisible by 3
            lis.append((i,'three!'))
        #checking if number is divisible by 5
        elif(i%5==0):
            #adding to lis, tuple for divisible by 5
            lis.append((i,'five!'))
        else:
            #adding to lis, tuple for divisible by none
            lis.append((i,''))
    #retuning the list
    return lis
#calling gee_whiz function printing the list for a sample value 6
print(gee_whiz(6))

Screenshot:

Output: