Question

C++ Enumeration from A-Z, convert to the String on cout

So I have an Enumeration from A-Z such as Enum = (A, B, C, D, E, F.... Z)

When I go into a loop, the enumeration needs to + each iteration through the loop and give the name

For ex. Loop 1:

Name = 'A'

But print 'A' and not 1

++ Enumeration(Dont know if this works or not)

Loop 2:

Name = 'B'

but print 'B' and not 2

Loop 3:

Name = 'C'

but print 'C' and not 3

I believe this needs ascii conversion? Im just not sure how to get the enumeration to + each iteration? and if I need a seperate function? I NEED to use enum as a type.

Thank you!

Answer 1

// C++ program to Enumeration from A-Z, convert to the String on cout

#include <iostream>

using namespace std;

// we assign A to 65, all unassigned names gets value as value of previous name + 1

// the values assigned to enum names are integral constants

// Here A = 65, B=66, C= 67, ...., Z=90

enum Letter

{

       A=65,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z

};

int main()

{

       int x =A; // since enum values are integral constants, we can use int type variable to loop over the names of enum

       // loop to print the name (letter)

       for(;x<=Z;x++)

          cout<<(char)(x)<<endl; // we cast the integer to char while displaying

       return 0;

}

//end of program

Output: