prove log_2 n^2 = little o(log_2 n^3) without using limits
`Hey,
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Let f(n)=log2(n^2) and g(n)=log2(n^3)
So, f(n) can be written as
f(n)=2*log2(n) (Using log properties)
g(n)=3*log2(n) (Using log properties)
So,
f(n)<=(3/2)*g(n)
So, we can choose any constant c>3/2
So, f(n)<c*g(n)
where c>3/2 be it c=2
So,
f(n)=o(g(n)) using the little o definition
Kindly revert for any queries
Thanks.
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