Question

A five-sided closed field traverse has the following distances in feet: AB = 647.25; BC =...

A five-sided closed field traverse has the following distances in feet: AB = 647.25; BC = 203.03; CD = 720.35; and DE = 610.24; and EA = 285.13. The interior angles are as follows (measured as angles to the right): A = 100º 45' 37"; B = 231º 23' 43"; C = 17º 12' 59"; D = 89º 03' 28"; and E = 101º 34' 24". The bearing of AB is S 53º 04' 43" E. Determine the bearings of each side.

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