Answer is
HCl (aq) and NaCl (aq)
because equivalence point is not reached so there will be some HCl reamaining after some being nuetralized by NaOH added
NaOH will not be present as soon as it is added it will be nuetralized by the HCl so there will be no NaOH
as the reaction has proceeded NaCl would have been formed from the nuetralization reaction
HCl (aq) + NaOH (aq) -----> NaCl (aq) + H2O (l)
so before equivalence point NaCl and HCl will be present
but at equivalence point only NaCl will be present there will be no HCl and NaOH
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