Question

A titration is performed where a 10mL sample containing acetic acid is added to a flask with 40 mL of water,and three(3) drops of phenelphthalein. The end point of the titration is reached after 44.00mL of 0.1250 M NaOH has been added. A. Calculate the number of moles of NaOH used in the titration B. Calculate the number of moles of acetic acid in the sample. C.Calculate the Molarity of the acetic in the sample

Answer 1

number of mole of NaOH = (44 * 0.125) / 1000

                                              = 0.0055 moles

for number of moles of CH3COOH = 0.0055 moles

since 1 mole of NaOH requires 1mole of CH3COOH according to equation,

CH3COOH + NaOH -------------> CH3COO Na + H2O

molarity of CH3COOH = (0.0055 * 1000 / 50)

                                        = 0.11 mol / L

molarity of CH3COOH in 10 mL of sample = 0.11 * 50 /10

                                                                             = 0.55 M