Question

1. Suppose you are titrating a dilute acetic acid solution in a flask with NaOH in...

1. Suppose you are titrating a dilute acetic acid solution in a flask with NaOH in the buret. Acetic acid is a weak acid that has the formula CH3COOH and the following structure: Which three species are present in the largest quantities in the flask before any NaOH is added? H+, OH-, H2O, CH3COOH, CH3COO-

2.For the titration of a dilute acetic acid solution with NaOH, rank the following species from highest to lowest in terms of quantity at the equivalence point, 1=highest quantity 4=lowest quantity CH3COOH, H2O, OH-, CH3COO-

Homework Answers

Answer #1

Q1. The species present is largest quantities are : H2O , CH3COOH and H+

Explanation

Since the solution is a dilute solution, therefore largest quantity present will be water H2O. After that acetic acid CH3COOH will have the largest quantity since it is the solute. Acetic acid dissociates into hydrogen ions H+ and acetate ions CH3COO-

But H+ also comes from water dissociation into H+ and OH-. Therefore, the next largest species would be H+

Q2.

Species Ranking
H2O 1
CH3COO- 2
OH- 3
CH3COOH 4
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A solution of 0.1 M acetic acid (CH3COOH, pKa 4.76) was titrated with NaOH. (a) What...
A solution of 0.1 M acetic acid (CH3COOH, pKa 4.76) was titrated with NaOH. (a) What is the Ka of acetic acid? (b) What is the starting pH of this solution? (Assume that at equilibrium, [HA] = 0.1 M.) (c) What is the pH at the titration midpoint? (d) At this midpoint, [CH3COO- ] = [CH3COOH]. Did [H+ ] increase or decrease when OH- was added (relative to the starting point) and how did this change occur? (e) What is...
A sample of acetic acid (weak acid) was neutralized with .05M NaOH solution by titration. 34...
A sample of acetic acid (weak acid) was neutralized with .05M NaOH solution by titration. 34 mL of NaOH had been used. Show your work. CH3COOH + NaOH-----CH3COONa + H2O a) Calculate how many moles of NaOH were used? b) How many moles of aspirin were in a sample? c) Calculate how many grams of acetic acid were in the sample d) When acetic acid is titrated with NaOH solution what is the pH at the equivalence point? Circle the...
For all of the following questions 10.00mL of 0.187 M acetic acid (CH3COOH) is titrated with...
For all of the following questions 10.00mL of 0.187 M acetic acid (CH3COOH) is titrated with 0.100M KOH (The Ka of acetic acid is 1.80 x 10-5) Region 1: Initial pH Before any titrant is added to the starting material Tabulate the concentration of the species involved in the equilibrium reaction, letting x = [H+] at equilibrium (Do not calculate “x” yet) CH3COOH ⇌ H+(aq) CH3COO-(aq) Initial concentration (M) Change in concentration (M) -x +x +x Equilibrium concentration (M) Use...
Hi there, I am asked to calculate for the millimoles of acetic acid in a sample...
Hi there, I am asked to calculate for the millimoles of acetic acid in a sample for a lab (Determination of the molar mass and ionization constant of a weak acid) this lab was performed with titration of 0.10 M NaOH into a 30.615g of acetic acid. Measured pH of the acetic acid sol’n Trial 1 Mass of acetic acid sol’n taken for the tritation 30.615g Initial buret reading of NaOH tritrant 0.00ml Final buret reading of NaOH tritrant 12.6ml...
Background info: Vinegar contains acetic acid, CH3COOH. You can determine the mass of acetic acid in...
Background info: Vinegar contains acetic acid, CH3COOH. You can determine the mass of acetic acid in a vinegar sample by titrating with sodium hydroxide of known concentration. The reaction: CH3OOH(AQ) +NaOH(aq)=> CH3COONa(aq)+H2O(l). I have determined the grams of acetic acid to be 60. There are 25 ml sample of vinegar requiring 41.33 mL of a .953 M solution of NaOH by titrating sodium hydroxide of known concentration. ** THE QUESTION IS: What is the molar concentration of the acetic acid...
You are titrating 50mL of diprotic acid H2X with standardized 0.01M NaOH solution. It takes 25...
You are titrating 50mL of diprotic acid H2X with standardized 0.01M NaOH solution. It takes 25 mL of NaOH to reach the first equivalence point. a. Write down the balanced equation for each of the titration reactions b. What is the volume of base needed to reach the second equivalence point c. Calculate the concentration (M) of the unknown acid solution, H2X
A 22.5 mL sample of an acetic acid solution is titrated with a 0.175M NaOH solution....
A 22.5 mL sample of an acetic acid solution is titrated with a 0.175M NaOH solution. The equivalence point is reached when 37.5 mL of the base is added. What was the concentration of acetic acid in the original (22.5mL) sample? What is the pH of the equivalence point? Ka acetic acid= 1.75E-5
1)For a titration of 25.00mL of .1000M acetic acid with .1000M NaOH calculate the pH    ...
1)For a titration of 25.00mL of .1000M acetic acid with .1000M NaOH calculate the pH     a)before the addition of any NaOH solution     b) after 10.00mL of the base is added     c) after half the acid is neutralized     d) at the equivalence point 2) What is the pKa of the acid?
You determine the concentration of a solution of HCl by titration with NaOH. The titration reaction...
You determine the concentration of a solution of HCl by titration with NaOH. The titration reaction is: HCl(aq) + NaOH(aq) → H2O(l) + NaCl(aq) Using a volumetric pipet, you transfer 10.00 mL of the HCl solution into an Erlenmeyer flask, then dilute it with ~50 mL of water and add 3 drops of phenolphthalein. The endpoint is reached after you have added 44.00 mL of 0.1250 M NaOH solution from a buret. Calculate the molarity of the original HCl solution....
A titration involves adding a reactant of known quantity to a solution of an another reactant...
A titration involves adding a reactant of known quantity to a solution of an another reactant while monitoring the equilibrium concentrations. This allows one to determine the concentration of the second reactant. The equation for the reaction of a generic weak acid HA with a strong base is HA(aq)+OH−(aq)→A−(aq)+H2O(l) A certain weak acid, HA, with a Ka value of 5.61×10−6, is titrated with NaOH. A: A solution is made by titrating 7.00 mmol (millimoles) of HA and 2.00 mmol of...