The Claisen condensation produces 3-ketoesters. The reaction
mechanism can be summarized as follows:
- Formation of the enolate: this will take place on the alpha-H
(or the hydrogens of the alpha-C) to the carbonyl group. A base is
needed to take one alpha-H and produce the enolate.
- The negative charge on the O atom in the enolate moves to
create a C=O bond and the alkene double bond attacks the partially
positively charged C of the C=O group of the other compound.
- The product of step 2 will have a negatively charged O atom,
the negative charge electrons will move to form another C=O bond
and an alcoxide group will be released (generally this alcoxide
will act as the base in step 1 as the reaction goes on).
Mechanism and Answer
Note: this
reaction requires a lot of attention and care when it's being made
in the lab because the enolate can react with the compound it comes
from and not with the other compound (in easier words, A forms an
enolate that reacts with B, but if the reaction doesn't have a
proper handling, the enolate can react with A too).