Question

Glucose, C_​6​​H_​12O_​6 , is used as an energy source by the human body. The overall reaction in the body is described by the equation.

C6H12O6(aq)+6O2(g) ---> 6CO _​2(g)+6H_^​​2​O(l)

Calculate the number of grams of oxygen required to convert 58.0 g of glucose to CO_​2 and H​_​2​O

Also compute the number of grams of CO₂ produced.

Answer 1

Number of moles of glucose = 58.0 g / 180.0 g.mol^-1 = 0.322 mole

from the balanced equation we can say that

1 mole of glucose requires 6 mole of O2 so

0.322 mole of glucose will require

= 0.322 mole of glucose*(6 mole of O2 /1 mole of glucose)

= 1.932 mole of O2

1 mole of O2 = 32.0 g

1.932 mole of O2 = 61.8 g

Therefore, the amount of oxygen required is 61.8 g

from the balanced equation we can say that

1 mole of glucose produces 6 mole of CO2 so

0.322 mole of glucose will produce 1.932 mole of CO2

1 mole of CO2 = 44.01 g

1.932 mole of CO2 = 85.0 g of CO2 will be produced.