Consider the reaction, 2 CO(g) + O2(g) ---------> 2 CO2(g)
molecular weights, 2x(12+16) 32g --------> 2x(12+32)
56g 32g 88g
That is if 56 g of CO can produce 88g CO2 when reacting with 32 g of oxygen.
So, 1 g of CO require 32/56 g of Oxygen
So 10 g of CO require, 10 x (32/56) = 5.714 g of oxygen.
How much CO2 will get?
from 56 g CO and 32 g O2 , 88 g of CO2 will get as the product
So from 10 g CO, you will get (88/56)x10 = 15.7142g of CO2 will get.
Now, efficiency? instead of 15.714g of CO2 (expecting), only getting 6g.
Efficiency = =38.1825%.
i hope you got the answer.
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