Question

C₆H₁₂O₆(aq) + 6O₂(g) --> 6CO₂(g) + 6H₂O(l)

Calculate the number of grams of oxygen required to convert 28.0g of glucose to CO₂ and H₂O

Also compute the number of grams of CO₂ produced.

Answer 1

Molar mass of Glucose = 180 g/mol

mass of Glucose = 28 g

Number of Glucose = mass/molar mass = 28/180 =0.156 mol

1 mol of glucose requires 6 mol of O2

So, number of moles of O2= 6*0.156 =0.933 mol

Molar mass of O2= 32 g/mol

So,

mass of O2 = number of moles * molar mass

                 = 0.933*32

                  =29.9 g

1 mol of glucose produces 6 mol of CO2

So, number of moles of CO2= 6*0.156 =0.933 mol

Molar mass of CO2 = 12+32= 44 g/mol

mass of CO2 = molar mass * number of moles

                    = 44*0.933

                    =41.1 g