Question

# C6H12O6(aq) + 6O2(g) --> 6CO2(g) + 6H2O(l) Calculate the number of grams of oxygen required to...

C6H12O6(aq) + 6O2(g) --> 6CO2(g) + 6H2O(l)

Calculate the number of grams of oxygen required to convert 28.0g of glucose to CO2 and H2O

Also compute the number of grams of CO2 produced.

#### Homework Answers

Answer #1

Molar mass of Glucose = 180 g/mol

mass of Glucose = 28 g

Number of Glucose = mass/molar mass = 28/180 =0.156 mol

1 mol of glucose requires 6 mol of O2

So, number of moles of O2= 6*0.156 =0.933 mol

Molar mass of O2= 32 g/mol

So,

mass of O2 = number of moles * molar mass

= 0.933*32

=29.9 g

1 mol of glucose produces 6 mol of CO2

So, number of moles of CO2= 6*0.156 =0.933 mol

Molar mass of CO2 = 12+32= 44 g/mol

mass of CO2 = molar mass * number of moles

= 44*0.933

=41.1 g

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