Question

for questions A through D:
3 vessels are submerged in a tank of water held at 87.33° C and connected by stopcocks which are currently closed. Vessel A has volume of 2.0000 L , and contains 2.5000 moles of H2, vessel B has 37.628 g of CO at a p=18.376 atm and vessel C has 143.91 g of O2 in 3.5000L. Assuming these are ideal gases, calculate the following:

A) The pressure in vessel A:

B) The volume in vessel B:

C) The pressure in vessel C:

D) If the stopcock is opened between vessel B and C, and all of the CO2 in vessel B is pushed into vessel C with the O2, what would be the total pressure in vessel C and the partial pressure of each gas?
Pt=               ,Po2=                  ,Pco2=

Answer 1

PV = nRT

PA = nRT/V = 2.5*0.082*(87.33+273)/2 = 36.9338 atm

PC = nRT/V = (143.91/32)*0.082*(87.33+273)/3.5 = 37.965 atm

Vb = nRT/P = (37.628/44)*0.082*(87.33+273)/18.376 = 1.3750 L

d)

total volume = 2+3.5 + 1.3750 = 6.875 L

total mol = 2.5 + 143.91/32+37.628/44 = 7.8523 mol

so..

Total P

P = nRT/V = 7.8523*0.082*(87.3++273)/6.875 = 33.74444 atm

so..

mol frac -->

O2 = ( 143.91/32) / 6.875 = 0.6541

CO2 = 37.628/44 / 6.875 = 0.1243

so...

PO2 = xO2* PT = 0.6541 *33.74444 = 22.072 atm

PCO2 = xCO2* PT = 0.1243*33.74444 = 4.194 atm