Question

What are the clear cut differences and similarities in the acid hydrolysis of [Co(NH3)5MoO4] + and [Co(NH3)5CrO4] +? Do you see anything that relates to the terms “labile” and ‘inert” here? What happens to the coordination numbers of the metal centers? Why????

Answer 1

bith the complex will give [Co(H₃O⁺)₆]3+,d⁶ electrons atr all fill in to t₂g set so hydrated Co(III) is more stable it is innert

[Co(NH3)5MoO4] +,[Co(NH3)5CrO4] +are d^{7 , in this one electron} e_g^* antibonding orbital are free some what labile nature, chromium(III) ion ligand is some waht innert compare to Mo(III) ligand, 6 coordination number in this complex 5 NH₃,one chromium(III) ion ligand(Oxigen is directly binding to the central metal ion same thing in Mo(III) ligand also