Question

Suppose a reaction has the equilibrium constant K= 1.3 x 10^8. What does the magnitude of...

Suppose a reaction has the equilibrium constant K= 1.3 x 10^8. What does the magnitude of this constant tell you about the relative concentrations of products and reactants that will be present once equilibrium is reached? Is this reaction likely to be a good source of the products?

Homework Answers

Answer #1

Kc is defined as concentration of product by concentration of reactant with each concentration term raised to power that is equal to its stoichiometric coefficient in balanced equation

So,

Kc = [product]/[reactant]

Since Kc is large value in question

So,

[product] > reactant

The amount of product is much more larger than that of reactant.

So, It is a good source of product.

The amount of product is much more larger than that of reactant.

good source of product.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Which of the following statements is a true statement concerning a reaction that has reached a...
Which of the following statements is a true statement concerning a reaction that has reached a state of equilibrium? A system has reached equilibrium when there are equal amounts of products and reactants present in the system. A system has reached equilibrium when the rate constant for the forward reaction equals the rate constant of the reverse reaction. A system has reached equilibrium when the reaction has stopped and no more products are formed. A system has reached equilibrium when...
Calculating Equilibrium Constants. The equilibrium constant, K, of a reaction at a particular temperature is determined...
Calculating Equilibrium Constants. The equilibrium constant, K, of a reaction at a particular temperature is determined by the concentrations or pressures of the reactants and products at equilibrium. For a gaseous reaction with the general form aA+bB⇌cC+dD the Kc and Kp expressions are given by Kc=[C]c[D]d[A]a[B]b Kp=(PC)c(PD)d(PA)a(PB)b The subscript c or p indicates whether K is expressed in terms of concentrations or pressures. Equilibrium-constant expressions do not include a term for any pure solids or liquids that may be involved...
A. The equilibrium constant, Kc, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g)<---> CH4(g)...
A. The equilibrium constant, Kc, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g)<---> CH4(g) + CCl4(g) Calculate the equilibrium concentrations of reactant and products when 0.346 moles of CH2Cl2 are introduced into a 1.00 L vessel at 350 K. B. The equilibrium constant, Kc, for the following reaction is 9.52×10-2at 350 K. CH4(g) + CCl4(g) <---> 2 CH2Cl2(g) Calculate the equilibrium concentrations of reactants and product when 0.200 moles of CH4and 0.200 moles of CCl4are introduced into a...
The equlibrium constant K, for the following reaction is 2.00 x 10-2 at 613 K. COCl2(g)...
The equlibrium constant K, for the following reaction is 2.00 x 10-2 at 613 K. COCl2(g) CO(g) + Cl2(g) An equilibrium mixture of the three gases in a 18.4 L container at 613 K contains 0.194 M COCl2, 6.22 x 10-2 M CO and 6.22 x10-2 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if the equilibrium mixture is compressed at constant temperature to a volume of 7.62 L? [COCl2]= _____________M [CO]=____________M...
The equilibrium constant, Kc, for the following reaction is 9.52×10-2 at 350 K. CH4 (g) +...
The equilibrium constant, Kc, for the following reaction is 9.52×10-2 at 350 K. CH4 (g) + CCl4 (g) <-> 2 CH2Cl2 (g) Calculate the equilibrium concentrations of reactants and product when 0.281 moles of CH4 and 0.281 moles of CCl4 are introduced into a 1.00 L vessel at 350 K. [CH4] = [CCl4] = [CH2Cl2] =
The reaction below has an equilibrium constant of Kp=2.26×104 at 298 K. CO(g)+2H2(g)⇌CH3OH(g) Part A Calculate...
The reaction below has an equilibrium constant of Kp=2.26×104 at 298 K. CO(g)+2H2(g)⇌CH3OH(g) Part A Calculate Kp for the reaction below. CH3OH(g)⇌CO(g)+2H2(g) K = Part B Predict whether reactants or products will be favored at equilibrium in the reaction above. Products will be favored at equilibrium. Reactants will be favored at equilibrium. Part C Calculate Kp for the reaction below. 12CO(g)+H2(g)⇌12CH3OH(g) K = Part D Predict whether reactants or products will be favored at equilibrium in the reaction above. Products...
The equilibrium constant, K, for the following reaction is 1.29×10-2 at 600 K. COCl2(g) CO(g) +...
The equilibrium constant, K, for the following reaction is 1.29×10-2 at 600 K. COCl2(g) CO(g) + Cl2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 600 K contains 0.244 M COCl2, 5.61×10-2 M CO and 5.61×10-2 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.44×10-2 mol of CO(g) is added to the flask? [COCl2] = M [CO] = M [Cl2] = M
The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) H2(g) +...
The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) H2(g) + I2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.325 M HI, 4.36×10-2 M H2 and 4.36×10-2 M I2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 2.27×10-2 mol of I2(g) is added to the flask? [HI] = _____M [H2] = ____M [I2] = _____M
The equilibrium constant, K, for the following reaction is 5.10×10-6 at 548 K. NH4Cl(s) --> NH3(g)...
The equilibrium constant, K, for the following reaction is 5.10×10-6 at 548 K. NH4Cl(s) --> NH3(g) + HCl(g) An equilibrium mixture of the solid and the two gases in a 1.00 L flask at 548 K contains 0.255 mol NH4Cl, 2.26×10-3 M NH3 and 2.26×10-3 M HCl. If the concentration of HCl(g) is suddenly increased to 3.55×10-3 M, what will be the concentrations of the two gases once equilibrium has been reestablished? [NH3] = M [HCl] = M
The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) --> H2(g)...
The equilibrium constant, K, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) --> H2(g) + I2(g) An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.322 M HI,   4.33×10-2 M H2 and 4.33×10-2 M I2. What will be the concentrations of the three gases once equilibrium has been reestablished, if 0.213 mol of HI(g) is added to the flask? [HI] = M [H2] = M [I2] = M