an aluminum soda can having a mass of 12.537 g is
treated with lithium hydroxide followed by sulfuric and (both in
excess) to yield lithium alum dodecahydrate (442.23 g/mol)
according to the equation. 2Al (s) + 2LiOH (aq) + 4H2SO4 (aq) +
22H2O (I) -》 2LiAI (SO4)2•12H2O (s) + 3H2 (g)
if the actual mass recovered was 149.3 g what was the percent yield?
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