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how many grams of barium chloride (BaCl2) are there in 0.337 moles

how many grams of barium chloride (BaCl2) are there in 0.337 moles

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Answer #1

given      no of moles = 0.337 moles

                     mol wt =    137+ 71 = 208

           no of moles =   weight   /   mol wt

                0.337    =    w /   208

                       w =   0.337*   208   = 70.096 g

               thank u

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