Question

When 0.629g of Na2PO4•12H2O and 0.527g of BaCl2•2H2O are mixed with water forming 500 mL of...

When 0.629g of Na2PO4•12H2O and 0.527g of BaCl2•2H2O are mixed with water forming 500 mL of solution, how many grams of Ba3(PO4)2 precipitate?
I know what steps to take to figure out the problem, but my question is when calculating the molar mass of the sodium phosphate or barium chloride, am i also adding in the H2O in order to find moles?

Science   Chemistry   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
13. What is the experimental yield (in grams) of the solid product when the percent yield...
13. What is the experimental yield (in grams) of the solid product when the percent yield is 93.4 % when 9.946 g of barium chloride reacts in solution with excess sodium phosphate? BaCl2(aq) + Na3PO4(aq) --> Ba3(PO4)2(s) + NaCl(aq) [unbalanced]
How many grams of Ba3(PO4)2 can be made when 100 mL of 0.300 M BaCl2 are...
How many grams of Ba3(PO4)2 can be made when 100 mL of 0.300 M BaCl2 are allowed to react with 50.0 mL of 0.800 M Na3PO4?
I am stuck at calculating mass of excess reactant used up in the reaction and mass...
I am stuck at calculating mass of excess reactant used up in the reaction and mass of excess reactant left over after the reaction 2Na3PO4*12H2O + 3Ba Cl*2H2O --> Ba3(PO4)2 + 6NaCl + 30H2O I got mass of precipitate : 0.063 Initial Mass of salt mixture 0.063 Moles of Ba3(PO4)2 precipitated: 1.04*10^-4 Moles of limiting reactant in the sal mixture : 3.14x10^-4 Mass of Limiting reactant in the salt Mixture :0.077 g Mass of excess reactant in the salt mixture...
How many grams of solid barium phosphate form when 48.3 mL of 0.087 M Barium Chloride...
How many grams of solid barium phosphate form when 48.3 mL of 0.087 M Barium Chloride reacts with 34.0 mL of 0.155 M Sodium phosphate? What is the limiting reactant? if the percent yield is 76% how much barium phosphate is recovered?
When 1.30 x 102 mL of 0.0100 M BaCl2 is mixed with 1.50 x 102mL of...
When 1.30 x 102 mL of 0.0100 M BaCl2 is mixed with 1.50 x 102mL of 0.00500 M H2SO4, what mass of precipitate is formed ? show working out
What is the experimental yield (in g of precipitate) when 16.5 mL of a 0.633 M...
What is the experimental yield (in g of precipitate) when 16.5 mL of a 0.633 M solution of barium hydroxide is combined with 17.3 mL of a 0.521 M solution of aluminum nitrate at a 89.6% yield? What is the theoretical yield (in g of precipitate) when 16.4 mL of a 0.559 M solution of iron(III) chloride is combined with 16.9 mL of a 0.577 M solution of lead(II) nitrate? What is the theoretical yield (in g of precipitate) when...
How many grams of iron III sulfate form when 62.0 mL of 0.160 M of Barium...
How many grams of iron III sulfate form when 62.0 mL of 0.160 M of Barium chloride reacts with 58.0 ml of 0.065 M os Sodium Sulfate? Please show the steps necessary to reach the answer as well. This question is not in the textbook solutions section of chegg.
How many grams of iron III sulfate form when 62.0 mL of 0.160 M of Barium...
How many grams of iron III sulfate form when 62.0 mL of 0.160 M of Barium chloride reacts with 58.0 ml of 0.065 M os Sodium Sulfate? Please show the steps necessary to reach the answer as well. This question is not in the textbook solutions section of chegg.
1.Use a permanent marker to label three test tubes "Carbonate Ion Test," "Sulfate Ion Test" and...
1.Use a permanent marker to label three test tubes "Carbonate Ion Test," "Sulfate Ion Test" and "Phosphate Ion Test. 2.Use the 10 mL graduated cylinder to measure and pour 2 mL of the unknown solution into each test tube. 3.Perform the Carbonate Ion Test by pipetting five drops of acetic acid into the test tube labeled "Carbonate Ion Test 4.Perform the Sulfate Ion Test by pipetting one drop of acetic acid (using the pipette from Step 5) and four drops...
When 1.3584 g of sodium acetate trihydrate was mixed into 100.0 mL of 0.2000 M HCl...
When 1.3584 g of sodium acetate trihydrate was mixed into 100.0 mL of 0.2000 M HCl (aq) at 25˚C in a coffee-cup calorimeter, its temperature fell by 0.397˚C. The reaction occurring is as follows: H3O+(aq) + NaCH3CO23 H2O (s) Na+ (aq) + CH3COOH (aq) + 4H2O() a) The heat capacity of the calorimeter is 91.0 J/˚C. Determine the enthalpy of reaction (in kJ/mol). Describe any assumptions that you made. b) Determine the standard enthalpy of formation for the solid sodium...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT