Question

According to the following reaction, how many grams of barium hydroxide are required for the complete reaction of 24.8 grams of hydrochloric acid?

hydrochloric acid(aq) + barium hydroxide(aq) --> barium chloride(aq) + water(l)

grams barium hydroxide

Answer 1

balanced equation is

2HCl + Ba(OH)₂ ------> BaCl₂ + 2H2O

number of moles of HCl = 24.8g / 36.4609 g.mol^-1 = 0.680 mole

from the balanced equation we can say that

2 mole of HCl requires 1 mole of barium hydroxide so

0.680 mole of HCl will require

= 0.680 mole of HCl*(1 mole of barium hydroxide /2 mole of HCl)

= 0.340 mole of barium hydroxide will be required.

1 mole of barium hydroxide = 171.34g

0.340 mole of barium hydroxide = 58.3 g

therefore, the mass of barium hydroxide required is 58.3g