Question

According to the following reactions:

A) how many grams of potassium sulfate are required for the complete reaction of 22.0 grams of barium chloride?

barium chloride(aq) + potassium sulfate(aq) --> barium sulfate(s) + potassium chloride(aq)

B) how many grams of hydrogen peroxide (H₂O₂) are needed to form 32.8 grams of oxygen gas?

hydrogen peroxide (H₂O₂)(aq) --> water(ℓ) + oxygen(g)

Answer 1

A. 1 Mole of of BaCl2 is required to react with 1 mole of Sodium Sulfate.

hence, number of moles of BaCl2 = 22g/208.23gmol^-1

= 0.1055 mole

Therefore, 0.1055 moles of Sodium sulfate reacts with 0.1055 moles of BaCl₂.

Molecular weight of K₂SO₄ is 174.259 g/Mol.

amount of K₂SO_{4 i}n grams = moleular weight of K2SO4 x 0.1055

= 174.259 g/mol x 0.1055mol

=18g

18g of K₂SO₄ is required to react wiht 22g of BaCl₂

  

B. 1 mole of H₂O₂ produces half moles of Oxygen.

i.e., 34.0147 g/mol of H2O2 produces 15.999 g of Oxygen.

what amount of H₂O₂ is required to produce 32.8 g of Oxygen.

= 32.8 x 34.014/15.99

=69.772 g.

Therefore, 69.772 g of H₂O₂ is reqired to produce 32.8 g of H₂O₂