If one dissolves 0.1 mole of Fe (NO3)3 (s) in 1 L of water, what is the total ionic concentration?
Fe (NO3)3 concentration = moles / volume
= 0.1 / 1
= 0.1 M
Fe (NO3)3 -----------------------> Fe+3 + 3 NO3-
total ions = 1 + 3 = 4
total ionis concentration = 4 x 0.1 = 0.4 M
total ionis concentration = 0.4 M
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