Question

3. Consider the following redox reaction, 3 Fe(NO3)2 (aq) + 2 Al (s) → 3 Fe (s) + 2 Al(NO3)3 (aq) a) Identify the species getting oxidized and the species getting reduced. b) If 6.3 moles of Fe(NO3)2 reacts with 5.4 moles of Al, which reactant is the limiting reactant? and c) How many grams of Al(NO3)3 will be produced?

Answer 1

3 Fe(NO3)2 (aq) + 2 Al (s) → 3 Fe (s) + 2 Al(NO3)3 (aq)

a) Fe = undergoes reduction.   Al = undergoes reduction.

b) 3 moles of Fe(NO3)2 gives ------> 2 moles of Al(NO3)3

6.3 moles of Fe(NO3)2 gives ------> 2*6.3/3 = 4.3 moles of Al(NO3)3.

2 moles of Al gives -------> 2 moles of Al(NO3)3

5.4 moles of Al gives ------> 2 * 5.4/2 = 5.4 moles of Al(NO3)3

so, Fe(NO3)2 is the limiting reagent.

c) moles of Al(NO3)3 formed = 4.3

mass of Al(NO3)3 = 4.3 * 213 = 894.6 grams.