The binding energy for electrons in cesium is 3.43 x 10^-19 J. What colors of light will eject electrons from cesium . Answer: yellow and shorter wavelenghts. How do I know. Also, If the uncertainty in the position of sodium atom were 10^-4 meter what is the uncertainty in its speed. Please explain. I'm unsure of what is meant by uncertainty.
Binding energy = 3.43 * 10-19 J
Binding energy = hv0
Where, h = planck's constant and v0 = threshold frequency
v0 = (3.43 * 10-19) / 6.625 * 10-34
v0 = 5.177 * 1014
wavelength = c / v0
where, c = speed of light
wavelength = (3 * 108) / (5.177 * 1014)
= 5.79 * 10-7
And this wavelength corresponds to Yellow color.
Using Heisenberg's Uncertainty principle
ΔpΔx = h
Where, Δp is uncertainty in momentum and Δ is uncertainty in postion and h is planck's constant.
m*Δv*Δx = h
Δv = 6.625 * 10-34 / (10-4 * 23 * 10-8)
= 2.88 * 10-23
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