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using the given data, calculate the rate constant of this reaction. A+B yields C+D Trial: 1,2,3...

using the given data, calculate the rate constant of this reaction. A+B yields C+D Trial: 1,2,3 [A](M): 0.370, 0.370, 0.592 [B](M):0.340, 0.782, 0.340 Rate(M/s): 0.0210, 0.111, 0.0336 K= ? Please provide the units as well. Please show work so I can understand the problem.

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Answer #1

R = k (A)m (B)n

0.0210= k (0.370)m (0.340 )n ------------ 1

0.111 = k (0.370)m (0.782 )n ------------ 2

0.0336 = k (0.592)m (0.340 )n ------------ 3

Now,

Divide eqn.-1 by eqn-2.

(0.0210) /(0.111) =( k (0.370)m (0.340 )n ) / k (0.370)m (0.782 )n

0.1892 == (0.4347)n

Taking log on both sides,

So, n=2.0

Now.

Divide eqn.-1 by eqn-3.

0.0210  /(0.0336) =( k (0.370)m (0.340 )n ) / k (0.592)m (0.340)n

0.625 ==(0.625)m

So, m=1

overall order = m+n = 2+1 = 3

From equation-1:

0.0210 = k (0.370 )1(0.340)2

k = 0.49

units of k in third order is M-2 s-1

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