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C6H12O6 + 6O2 ------> 6CO2 + 6 H2O If 856 g of C6H12O6 is consumed by...

C6H12O6 + 6O2 ------> 6CO2 + 6 H2O

If 856 g of C6H12O6 is consumed by a person over a certain period, what is the mass in g and volume in mL of CO2 produced at STP (1 mol= 22.414 L)?

***PLEASE show work so I can better understand the math set-up behind these problems.

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