Consider this reaction: 6CO2 + 6H2O ----> C6H12O6 + 6O2
Calculate the deltaG(degrees) for this reaction using the following Gibb's free energy of formation values:
Molecule: G(degrees)f(kJ)
CO2 -394.4
H2O -237.2
C6H12O6 -917.3
O2 0
G of the reaction = Products free energy values - Reactants free energy values
moles also considered
G = [ -917.3] - [ (6 x-394.9) + (6 x -237.2)] Oxygen value given Zero.
G = [ -917.3] - [ -2369.4-1423.2]
G = -917.3 + 3792.6
G = 2875.3 KJ.
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