Question

In the following reaction, how many grams of hydrogen, H2, will be produced from 53.5 g of aluminum, Al? 2Al + 3H2SO4 -> 3H2 + Al2(SO4)3

Answer 1

In the following reaction, how many grams of hydrogen, H₂, will be produced from 53.5 g of aluminum, Al?

2Al + 3H₂SO₄ -> 3H₂ + Al₂(SO₄)₃

From equation, from 2moles of Al we will get 3moles of H₂.

First convert 53.5 g of Al into moles.

Al M.Wt = 27

Al moles = Wt/M.Wt = 53.5/27 = 1.98 moles

So, If 2 moles of Al generates 3 mloles of H₂

Then, from 1.98 moles of Al how H₂ will produce

=(1.98*3)/2 = 2.972 moles of H₂ will produce

Convert 2.972 moles into grams

Moles = wt/m.wt

H₂ m.wt = 2

Wt of H₂ = 2.972*2 = 5.944 grams of H2 will generate