Identification Number | Field Choice | Gender |
1 | Business | Male |
2 | Other | Female |
3 | Business | Female |
4 | Science | Female |
5 | Science | Male |
6 | Other | Female |
7 | Business | Male |
8 | Science | Male |
9 | Science | Male |
10 | Business | Female |
11 | Other | Female |
12 | Other | Male |
13 | Business | Male |
14 | Business | Female |
15 | Science | Male |
16 | Business | Female |
17 | Science | Male |
18 | Science | Female |
19 | Science | Female |
20 | Business | Female |
21 | Other | Male |
22 | Business | Male |
23 | Business | Female |
24 | Other | Male |
25 | Other | Male |
26 | Science | Male |
27 | Other | Female |
28 | Science | Male |
29 | Science | Male |
30 | Science | Female |
“Thirty” randomly “selected college-bound students in Portland, Oregon, are asked about the field they would like to pursue in college. The choices offered in the questionnaire are science, business, and other. The gender information also is included in the questionnaire.”
Produce a 90% confidence interval estimate for the proportion of students in Portland who would like to pursue business, using the format given in class. As this is your first time using the format this document steps you through it (somewhat).
1- State the name of the confidence interval estimate used
2- State the level of confidence and associated ?
3- Assess the conditions required for this estimation process, justifying your answers For each condition:
state the condition off the estimator summary sheet, explain why you think it is met or not.
1. The z-distribution confidence interval will be used here.
2. The level of confidence is 90% and ? = 1 - 0.90 = 0.10
3. In order to conduct a one-sample proportion z-test, the following conditions should be met:
p = 10/30 = 0.33
n*p = 10 ≥10
n⋅(1−p) = 20 ≥10
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