Question

The literature value for the K_(sp) of Ca(OH)_2 is 4.68x10^-6. How does the value you determined...

The literature value for the K_(sp) of Ca(OH)_2 is 4.68x10^-6. How does the value you determined in the lab compare with this result? Explain what may have caused your results to differ from value. (Clearly explain what may have happened. Should you have obtain the literature value? Clearly explain how this could have happened?)

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Answer #1

As per the question it is post lab question for determination of Ksp of calcium hydroxide.

The expected value for the Ksp = 4.68x10^-6

Your result must be different from the given value, which can be explained as

The value determined in the experiment is different from the literature value. It could be accounted for the temperature. solubility product value highly depends upon temperature. The Ksp given in literatures is measured at 298 K. So if the experiment is performed above this temperature the solubility product must be high.

If the experiment is performed below 298 K then the solubility product must be low.

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