Part A.)
0.30 M HBr
Express your answer using two decimal places.
pH=
Part B.)
3.5×10−4 M KOH
Express your answer using two decimal places.
pH=
Part C.)
4.7×10−5 M Ca(OH)2
Express your answer using two decimal places.
pH=
Part A.
0.30 M HBr
for strong acids,
pH = -log (conc. H+)
= -log ( 0.3)
pH = 0.52 ........... Answer
PART B
3.5×10−4 M KOH
[OH-]= 3.5 x 10^-4 M
pOH = - log (3.5 x 10^-4) = 3.46
pH = 14- pH
= 14-3.46
pH = 10.54 ................. Answer
PART C
4.7×10−5 M Ca(OH)2
[OH-]= 2 x 4.7 x 10^-5 = 9.4 x 10^-5 M ........... as Ca(OH)2
has 2 OH- ions
pOH = - log (9.4 x 10^-5) = 4.02
pH = 14 - 4.02
pH = 9.98 ............. Answer
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