Calculate the pH of each solution.
Part A
[OH−] = 6.8×10−11 M
Express your answer using two decimal places.
Part B [OH−] = 3.6×10−3 M Express your answer using two decimal places. Part C [OH−] = 8.8×10−12 M Express your answer using two decimal places. Part D [OH−] = 9.4×10−4 M Express your answer using two decimal places. |
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A)
we have below equation to be used:
pOH = -log [OH-]
= -log (6.8*10^-11)
= 10.17
we have below equation to be used:
PH = 14 - pOH
= 14 - 10.17
= 3.83
Answer: 3.83
B)
we have below equation to be used:
pOH = -log [OH-]
= -log (3.6*10^-3)
= 2.4437
we have below equation to be used:
PH = 14 - pOH
= 14 - 2.4437
= 11.5563
Answer: 11.56
C)
we have below equation to be used:
pOH = -log [OH-]
= -log (8.8*10^-12)
= 11.0555
we have below equation to be used:
PH = 14 - pOH
= 14 - 11.0555
= 2.9445
Answer: 2.94
D)
we have below equation to be used:
pOH = -log [OH-]
= -log (9.4*10^-4)
= 3.0269
we have below equation to be used:
PH = 14 - pOH
= 14 - 3.0269
= 10.97
Answer: 10.97
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