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Problem 16.45 part 2 Part E Calculate [OH−] for 1.60 mL of 0.130 M NaOH diluted...

Problem 16.45 part 2

Part E

Calculate [OH−] for 1.60 mL of 0.130 M NaOH diluted to 1.50 L .

Express your answer using three significant figures.

[OH−] =   M  

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Part F

Calculate pH for 1.60 mL of 0.130 M NaOH diluted to 1.50 L .

Express your answer using three decimal places.

pH =

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Part G

Calculate [OH−] for a solution formed by adding 4.70 mL of 0.150 M KOH to 20.0 mL of 6.0×10−2 M Ca(OH)2.

Express your answer using two significant figures.

[OH−] =   M  

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Part H

Calculate pH for a solution formed by adding 4.70 mL of 0.150 M KOH to 20.0 mL of 6.0×10−2 M Ca(OH)2.

Express your answer using two decimal places.

pH =

Homework Answers

Answer #1

part E )

Calculate [OH−] for 1.60 mL of 0.130 M NaOH diluted to 1.50 L .

[OH-] = millimoles / total volume (mL)

         = 1.60 x 0.130 / (1.60 + 1500)

         = 1.38 x 10^-4 M

part F )

pOH = -log [OH-] = -log (1.38 x10^-4) = 3.86

pH + pOH = 14

pH = 10.142

Part G

[OH-] = ( 4.70 x 0.150 + 2 x 20 x 6 x 10^-2 ) / (4.70 +20.0)

[OH-] = 0.13 M

part H

pOH = -log [OH-] = 0.90

pH + pOH = 14

pH = 13.10

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