Question

Calculate the total masses of the reactants for the following equation:
2SeO2(g)+O2→2SeO3(g)

Express your answer to five significant figures and include the appropriate units.Calculate the total masses of the reactants for the following equation:

Please show me how this is done, Thank you!

Answer 1

Since no specified mass is mentioned in the question, I considering the molar mass for the said reaction.

Now,

2SeO₂(g) + O₂ →2SeO₃(g)

In the above reaction two moles SeO₂ of reacts 1 mole of O₂ to produces 2 moles of SeO₃.

Molar mass of

SeO₂ = 110.96 g/mol

O₂ = 16 g/mol

SeO₃ = 126.96 g/mol

2 moles of SeO₂ = (2 x 110.96) g = 221.92 g

1 mole of O₂ = (2 x 16) g = 32 g

So, the total molar mass of the reactants = 221.92 g + 32 g = 253.92 g.

Total  molar mass of the product = (2 x 126.96) g = 253.92 g