Question

Calculate the mass of butane needed to produce 82.6 g of carbon dioxide. Express your answer to three significant figures and include the appropriate units.

Answer 1

2C4H10 + 13O2 ------> 8CO2 + 10H2O

no of moles of CO2 = W/G.M.Wt

                                       = 82.6/44 = 1.877 moles

from balanced equation

8 moles of Co2 produced from 2 moles of C4H10

1.877 moles of CO2 produced from = 2*1.877/8   = 0.47 moles of C4H10

mass of C4H10 = no of moles * gram molar mass

                           = 0.47*58   = 27.3g of C4H10