How much dry solute would you take to prepare each of the following solutions from the dry solute and the solvent?
A.) 132 mL of 0.115 M NaNO3
B.) 124 g of 0.220 m NaNO3
C.) 124 g of 1.4 % NaNO3 solution by mass
D.) How much solvent would you take to prepare the solution in part B?
E.) How much solvent would you take to prepare the solution in part C?
Mass of solution = mass of solute + mass of solvent
124 g = (85 x 0.0229)g + mass of solvent
Mass of solvent = 122 g
E) 1.736 g of dry solute is present in124 g of 1.4 % NaNO3 solution by mass
Mass of solution = Mass of solute + Mass of solvent
124 g = 1.736 g + Mass of solvent
Mass of solvent = 122.26 g
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