How much dry solute would you take to prepare each of the following solutions from the dry solute and the solvent?
Part A: 113 mL of 0.490 M KCl
Part B: 109 g of 0.510 m KCl
Part C: 109 g of 4.7 %% KCl solution by mass
Part D: How much solvent would you take to prepare the solution in part B?
Part E: How much solvent would you take to prepare the solution in part C?
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