Consider the following reaction: |
Part A If a reaction mixture initially contains 0.159 M SO2Cl2, what is the equilibrium concentration of Cl2 at 227 ∘C? |
SOCl2
SO2 + Cl2
initial
0.159
0 0
change
-x
+x +x
Equil 0.159
-x
x x
Kc =
[SO2][Cl2]/[SO2Cl2]
2.99 x 10-7 = (x)(x)/(0.159 - x)
neglect x in the 0.159-x
x2 = 4.75 x 10-8
x = 2.18 x 10-4 = [Cl2] =
[SO2]
Get Answers For Free
Most questions answered within 1 hours.