Use the Pumping Lemma to prove that the language over Σ = {0,1} shown below is not regular. L6 = {anbncn : n ≥ 0}
We prove by contradictions with proper counterexamples. Assume p is the magic number. Choose w = apbpcp . Let w = xyz where |xy| <= p, and |y| >0. Then which of the following strings will lead to a contradiction to the pumping lemma.
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