Question

Bromomethane is converted to methanol in an alkaline solution. The reaction is first order in each...

Bromomethane is converted to methanol in an alkaline solution. The reaction is first order in each reactant.
CH3BR(aq)+OH-(aq)=CH3OH(aq)+Br-(aq)
Write the rate law. What is the overall order of the reaction?
How does the reaction rate change if the OH- concentration is decreased by a factor of 5?
What is the change in rate if the concentrations of both reactants are doubled?

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Homework Answers

Answer #1

a) Is a first order reaction for every reactant, this means that the overall order of reaction is 1 too. The rate law is the following:

Rate = k[CH3Br][OH-]

b) If concentration of OH is decreased by 5, then:

Rate = K[CH3Br]([OH-]/5)

The rate of the reaction will also decrease 5 times. Suppose that concentrations of CH3Br and OH are 0.5 and 0.25.and k is 0.007 (I'm just supposing these values to explain better the decrease) you'll have the following:

rate = 0.007 * 0.5 * 0.25 = 8.75x10-4

rate 2 = 0.007 * 0.5 * 0.25/5 = 1.75x10-4

This confirms that the rate is decrease by a factor of 5.

c) If both concentrations are doubled then the rate will increase by 4:

rate 3 = 0.007 * 1 * 0.5 = 3.5x10-3

8.75x10-4 * 4 = 3.5x10-3

Hope this helps

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