Question

Methyl Acetate reacts in alkaline solution to produce acetate and methanol according to the reaction below:...

Methyl Acetate reacts in alkaline solution to produce acetate and methanol according to the reaction below:

CH3COOCH3(aq) + OH-(aq) → CH3COO-(aq) + CH3OH (aq)

i) In an experiment, the concentration of methyl acetate was monitored as a function of time. The data is given in the table below. Complete the table below by converting the concentration data to an appropriate form that can be plotted to determine whether this reaction is first or second order. Show one example calculation for each column.

Time(min)

[CH3COOCH3] mol/L ([1])

1st Order

2nd Order

0.00

0.01000

5.00

0.00634

10.00

0.00463

20.00

0.00304

30.00

0.00224

ii) Using the values you calculated in i), Plot your data on the graph paper provided assuming a first order reaction and a second order reaction respectively.    Indicate axis titles, values etc.

First Order

Draw the graph

Second Order

Draw the graph

iii) From your graphs determine the actual order of the reaction with respect to methyl acetate.

iv) Calculate the rate constant for the reaction.

I need to know how to do these questions not just the answers, thank you!

Homework Answers

Answer #1

R = k[CH3COOCH3]n

ln(R) = ln(k) + n ln([CH3COOCH3])

y = c + mx

R = dC/dt (Needs to be determined from plotting concentration vs time and taking slope at time, t).

We need to plot Ln(R) vs Ln([[CH3COOCH3]), from the given table

iii) Actual order = 1.74

iv) Ln(k) = 1.12

k = 3.06

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