Question

consider the following system as equilibrium PbI2(s)= Pb2+(aq)+2I-(aq) how will adding more PbI2 shift the equilibrium?...

consider the following system as equilibrium PbI2(s)= Pb2+(aq)+2I-(aq)

how will adding more PbI2 shift the equilibrium?

how will removing some Pb2+ shift the equilibrium?

Homework Answers

Answer #1

Le Chatelier’s Principle:

According to this principle, whenever an equilibrium system is subjected to change, certain processes takes place which have a tendency to partially neutralize the initial change, which result in bringing the system to a new position of equilibrium. This principle mainly explains three different equilibrium changes:

  1. Equilibrium change due to change in the concentration
  1. Equilibrium change due to change in the volume or pressure
  1. Equilibrium change due to change in the temperature

consider the following system as equilibrium PbI2(s)= Pb2+(aq)+2I-(aq)

how will adding more PbI2 shift the equilibrium?

. If we add more solid PbI2 (s). No change.

The concentrations of the ions are already at equilibrium, so no more solid needs to dissolve. Thus, adding more solid will not shift the reaction.

how will removing some Pb2+ shift the equilibrium?

When will removing some Pb2+ to the reaction then equilibrium will shift to the right side or forward direction .

PbI2(s)= Pb2+(aq)+2I-(aq)

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