Question

aluminum is mined as the mineral bauxite, which consists primarily of Al2O3 (alumina). The aluminum can be refined by heating the bauxite to drive off the oxygen: 2Al2O3(s) ----> 4Al(s) + 3O2(g) part a) the aluminum produced from 4.20 x 10^3 kg of Al2O3. the oxygen produced in part a) is allowed to react with carbon to produce carbon monoxide. write a balanced equation describing the reaction of alumina with carbon. how much CO is produced from the alumina in part a?

Answer 1

2Al2O3(s) ----> 4Al(s) + 3O2(g)

6C + 3O2(g) -----------> 6CO

4.20 x 10^3 kg of Al2O3 = 4.2 x10³/101.96 = 41.19 Mole

If 41.19 Mole of Al2O3 reacts it will give (41.19 x 2) 82.38 mole of aluminium.

82.38 mole of aluminium = 82.38 x 26.98 = 2222 Kg of aluminium will be produced.

If 41.19 Mole of Al2O3 reacts it will give (41.19 x 3/2) 61.79 mole of oxygen

This 61.79 mole of oxygen wil react wil (61.79 x 2) 123.57 Mole of Carbon to give 123.57 mole of carbon monoxide

123.57 mole of CO = 123.57 x 28.01 = 3461.19 KG of CO will be produced