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12) A box contains 8 green marbles, 6 blue marbles, and 3 red marbles. Three marbles...

12) A box contains 8 green marbles, 6 blue marbles, and 3 red marbles. Three marbles are selected at random from the box, one at a time, without replacement. Find the probability that all three marbles selected are green. Round your answer to four decimal places.

Math   Statistics-And-Probability   
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Answer #1

Answer:

Given,

Green marbles = 8

Blue marbles = 6

Red marbles = 3

Total marbles = 8 + 6 + 3

= 17

Probability that the first ball is green = Number of green balls / Total balls

= 8 / 17

Probability of getting second ball is green = 7 / 16

Probability of getting third ball is green = 6 / 15

So now probability that all three marbles selected are green = Probability that the first ball is green * Probability of getting second ball is green * Probability of getting third ball is green

= 8/17 * 7/16 * 6/15

= 0.471*0.4375*0.4

= 0.0824

Required probability = 0.0824

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