Question

Find the density of acetic acid given mL of acetic acid used was 10mL and the...

Find the density of acetic acid given mL of acetic acid used was 10mL and the FW of acetic acid is 60.05g/mole.

Homework Answers

Answer #1

density = weight / volume is the formula, it does not depends on formula weight/ molar mass/molecular weight.

you have provided volume = 10 mL, but we need weight of acetic acid NOT FW, the standard value of density for acetic acid is 1.05 g/mL

please use density = weight of acetic acid in grams / volume in mL to get density.

i can skip this question with more information needed but i do not want to waste your valuable time. Please comment below still if you need any help from me as i am online now.

Hope this helped you!

Thank You So Much! Please Rate this answer as you wish.("Thumbs Up")

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
the density of a 6.27 M aqueous acetic acid solution is 1.045 g/ml. determine the molarity...
the density of a 6.27 M aqueous acetic acid solution is 1.045 g/ml. determine the molarity of this solution and mole fraction of acetic acid
A titration is performed where a 10mL sample containing acetic acid is added to a flask...
A titration is performed where a 10mL sample containing acetic acid is added to a flask with 40 mL of water,and three(3) drops of phenelphthalein. The end point of the titration is reached after 44.00mL of 0.1250 M NaOH has been added. A. Calculate the number of moles of NaOH used in the titration B. Calculate the number of moles of acetic acid in the sample. C.Calculate the Molarity of the acetic in the sample
Pure acetic acid, known as glacial acetic acid, is a liquid with a density of 1.049...
Pure acetic acid, known as glacial acetic acid, is a liquid with a density of 1.049 g/mL at 25 ∘C. Calculate the molarity of a solution of acetic acid made by dissolving 10.00 mL of glacial acetic acid at 25 ∘C in enough water to make 240.0 mL of solution. Please Explain.
Given the following atomic weights, that the density of acetic acid is 1.05, and that 7.0...
Given the following atomic weights, that the density of acetic acid is 1.05, and that 7.0 g of isoamyl alcohol, 6.6 mL of acetic acid, and 0.5 mL of sulfuric acid make 3.2 g of isoamyl acetate, what is the % yield of isoamyl acetate from its limiting reagent? Give at least two significant figures. C = 12, H = 1, O =16
1. How many moles are in 9.6 mL of acetic anhydride, density of 1.082? Give two...
1. How many moles are in 9.6 mL of acetic anhydride, density of 1.082? Give two significant figures. Given molecular weight: 102 g 2. As a "rule of thumb" there are 20 drops of a liquid in a mL. Using this estimate and a density of 1.685, how many moles are in 9 drops of 85 % by weight phosphoric acid? Give two significant digits. Given molecular weight: 98 g 3. Starting with 9.6 g of salicylic acid, how many...
Glacial acetic acid is 99.5% acetic acid (f.w. 60.052) by weight and has a density of...
Glacial acetic acid is 99.5% acetic acid (f.w. 60.052) by weight and has a density of 1.05g/mL. Calculate the volume of glacial acetic acid needed to make 1L of the 0.100M pH 5.000 buffer.
calculate the theoretical ph after the first addition of acid (HCL) for 10ml of .2m acetic...
calculate the theoretical ph after the first addition of acid (HCL) for 10ml of .2m acetic acid and 10ml .2m sodium acetate. first addition of acid is 1ml of      .099233m HCL.
Concentrated glacial acetic acid is 99.7% H3CCO2H by mass and has a density of 1.05 g/mL....
Concentrated glacial acetic acid is 99.7% H3CCO2H by mass and has a density of 1.05 g/mL. What is the molar concentration of concentrated glacial acetic acid?
Conversions Example 2) A 22% by mass solution of Acetic Acid ((C2H4O2)(MW=60.0520)) has a density of...
Conversions Example 2) A 22% by mass solution of Acetic Acid ((C2H4O2)(MW=60.0520)) has a density of 1.029 g/mL. What is the molarity, molality and mole fraction of the Acetic Acid in the solution? If you could show the steps as well that would be greatly appreciated! Thank you.
Find concentration of a weak acid given Volume of unknown acid, Molarity of bass(NaOH), and mL...
Find concentration of a weak acid given Volume of unknown acid, Molarity of bass(NaOH), and mL of bass(NaOH) at equalivance point. Volume unkown acid: 10mL Molality of bass: .18M mL bass at equvilance point: 6.1mL Find molarity of acid: ?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT