Question

Concentrated glacial acetic acid is 99.7% H3CCO2H by mass and has a density of 1.05 g/mL. What is the molar concentration of concentrated glacial acetic acid?

Answer 1

Let volume of solution be 1 L

volume , V = 1 L

= 1*10^3 mL

density, d = 1.05 g/mL

mass = density * volume

= 1.05 g/mL *1*10^3 mL

= 1050 g

This is mass of solution

mass of CH3COOH = 99.7 % of mass of solution

= 99.7*1050/100

= 1046.85 g

Molar mass of CH3COOH,

MM = 2*MM(C) + 4*MM(H) + 2*MM(O)

= 2*12.01 + 4*1.008 + 2*16.0

= 60.052 g/mol

mass(CH3COOH)= 1046.85 g

number of mol of CH3COOH,

n = mass of CH3COOH/molar mass of CH3COOH

=(1046.85 g)/(60.052 g/mol)

= 17.43 mol

volume , V = 1 L

Molarity,

M = number of mol / volume in L

= 17.43/1

= 17.43 M

Answer: 17.4 M