Question

Water's heat of fusion is 80. cal/g, and its specific heat is 1.0 cal/g.celsius. Some velomobile seats have been designed to hold ice packs inside their cushions. If you started a ride with ice packs that held 1200 of frozen water at 0 celsius , and the temperature of the water at the end of the ride was 32 celsius , how many calories of heat energy were absorbed?

Answer 1

0 --------- (2)-------------------> 32 0C

(1)

at 1 )   Q1 = m x heat of fusion = 1200 x 80 = 96000 cal

2 ) Q2 = m Cp dT = 1200 x 1 x (32-0) = 38400 cal

heat energy were absorbed = Q1 + Q1 = 96000 + 38400

                                               = 134400 cal