why is there a difference in reactivity of 1-bromobutane, 2-bromobutane, and 2-bromo-2-methylpropane?
generally alkyhalides undergo nucleophilic or elimination reactions
for SN1 or E1 substrate should be able to form stable carbocation that can undergo easily
so order will be
2-bromo-2-methylpropane > 2-bromobutane > 1-bromobutane
where as in case of SN2or E2 reaction
the carbon which is attached to halogen must be less substituted
then only nucleophile can come attack quickly if more and more substitution steric bulkyness is more rate of the reaction will be less
then order will be 1-bromobutane > 2-bromobutane > 2-bromo-2-methylpropane
Get Answers For Free
Most questions answered within 1 hours.