Arrange the alkyl halides in order of reactivity from most to least with AgNo3/Ethanol:
1) 2-bromobutane
2) 2-bromo-2-methyl pentane
3) 1-bromobutane
4) bromocyclohexane thank you
The reaction of haloalkane with AgNo3 /ethanol will take place via formation of carbonation. As we know greater the stability of the carbocation formed higher will be the reactivity. The order of stability of carbocation is:
3° > 2° >1°.
Because the alkyl group bonded to the positively charged carbon shows the electron releasing effect and thus make the carbocation more stable.
In 1) 2° carbocation will be formed when Br- is lost.
In 2)3° carbocation is formed.
In 3) 1° carbocation is formed.
In 4) cyclic 2° carbocation is formed.
Since cyclic cation will be more stable than primary but less than secondary . So the order of reactivity is:
2 > 1> 4 > 3
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