Question

(C language) <stdio.h> decisions (else if or switch)

Write a program to calculate the average of the 2 highest numbers entered. Ask the user to enter 3 integers, determine which 2 integers are the 2 highest, and then calculate and display the average of the 2 highest numbers. Format the answer to 2 decimal places.

The numbers can be entered in any sequence - lowest to highest, highest to lowest, or completely random. A decision block will be necessary to determine the 2 highest numbers. Since calculating an average involves division, type casting will be necessary.

Hints:

• You may find it easier to determine the lowest number, which means that the other 2 numbers are the 2 highest.
• Logical operators may be needed.

Example Run #1:

(bold type is what is entered by the user)

Enter the 1st integer: 2
Enter the 2nd integer: 3
Enter the 3rd integer: 4

The average of the 2 highest numbers
(3 and 4) is x.xx.

The example runs show EXACTLY how your program input and output will look.

Answer 1

#include <stdio.h>

int main() {
    int n1, n2, n3;
    printf("Enter the 1st integer: ");
    scanf("%d", &n1);
    printf("Enter the 2nd integer: ");
    scanf("%d", &n2);
    printf("Enter the 3rd integer: ");
    scanf("%d", &n3);
    if (n1 >= n3 && n2 >= n3) {
        printf("(%d and %d) is %.2f.\n", n1, n2, (n1+n2)/2.0);
    } else if (n2 >= n1 && n3 >= n1) {
        printf("(%d and %d) is %.2f.\n", n2, n3, (n2+n3)/2.0);
    } else {
        printf("(%d and %d) is %.2f.\n", n1, n3, (n1+n3)/2.0);
    }
    return 0;
}