Question

Calculate the volume of 50 % by mass NaOH needed to prepare 1.0L of 0.1 M...

Calculate the volume of 50 % by mass NaOH needed to prepare 1.0L of 0.1 M NaOH solution.

Homework Answers

Answer #1

Molarity of the solution = 0.1 M

Volume of solution = 1.0 L

50 % by mass NaOH means:

50 g NaOH present in 100 g of the solution.

500 g NaOH will be present in 1000 g solution.

Molar mass of NaOH = 39.997 g/mole

Moles of NaOH = Mass / Molar mass

= 500 / 39.997

= 12.5 moles

Volume of 1000 g solution = 1 L

Molarity of solution = 12.5 / 1 = 12.5 M

Now,

This NaOH solution is used to prepare 1.0L of 0.1 M NaOH solution.

Let volume V is required to prepare the solution.

M1V1 = M2V2

12.5 * V1 = 1.0 * 0.1

12.5 * V1 = 0.1

V1 = 0.1 / 12.5

V1 = 0.008 L

= 8 mL

Hence,

The volume required is 8 mL

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
How would you prepare :1500g of 40%solution NaOH ? Calculate mass of NaOH and volume of...
How would you prepare :1500g of 40%solution NaOH ? Calculate mass of NaOH and volume of H2O
What volume of a 50.0% by mass NaOH solution must be diluted to prepare a 500...
What volume of a 50.0% by mass NaOH solution must be diluted to prepare a 500 mL of 0.3500 M NaOH solution? The density of 50% NaOH solution is 1.515 g/ml at 25 degrees C.
Calculate the volume of 0.730-M NaOH solution needed to completely neutralize 58.9 mL of a 0.700-M...
Calculate the volume of 0.730-M NaOH solution needed to completely neutralize 58.9 mL of a 0.700-M solution of the monoprotic acid HBr. __________ mL NaOH
calculate the amount of each stock reagent needed to a. prepare 50 mL of .80 M...
calculate the amount of each stock reagent needed to a. prepare 50 mL of .80 M NaCl from 4.0 M NaCl stock. b.a. prepare 50 mL of .10 M NaCl from 4.0 M NaCl stock. c. prepare 50 mL of .30 M NaOH from 6.0 M NaOH stock. d.c. prepare 50 mL of .60 M NaOH from 4.0 M NaOH stock.
Calculate how many milliliters of 1 M NaOH will be needed to make 1 L of...
Calculate how many milliliters of 1 M NaOH will be needed to make 1 L of 0.1 M solution. Calculate how many grams of potassium acid phthalate (KHP, FW = 204.2 g/mol) will react with about 25 ml of the 0.1 M NaOH solution. The reaction is as follows: HKC8H4O4 + NaOH → H2O + NaKC8H4O4 Calculate how many mL of 1 M HCl is needed to make 1 L of 0.2 M HCl. HCl + NaOH → H2O +...
a) Calculate the volume of 0.0500 M NaOH needed to neutralize a mixture of 25.00 mL...
a) Calculate the volume of 0.0500 M NaOH needed to neutralize a mixture of 25.00 mL of 0.05 M HCl and 20.00 mL of 0.05 M NH4Cl. b) Calculate volume needed if 0.50 g of mannitol is added to acid mixture.
1. For the titration of 25.0 mL of 0.1 M HCl (aq) with 0.1 M NaOH...
1. For the titration of 25.0 mL of 0.1 M HCl (aq) with 0.1 M NaOH (aq), at what volume of NaOH (aq) should the equivalence point be reached and why? If an additional 3.0 mL of 0.1 M NaOH (aq) is then added, what is the expected pH of the final solution? 2. What is the initial pH expected for a 0.1 M solution of acetic acid? For the titration of 25.0 mL of 0.1 M acetic acid with...
How many millileters of 6.0M NaOH must be used to prepare 1.0L of 0.10M NaOH? Show...
How many millileters of 6.0M NaOH must be used to prepare 1.0L of 0.10M NaOH? Show calculation with units.
1). The volume of a stock 6 M NaOH solution required to prepare 250 mL of...
1). The volume of a stock 6 M NaOH solution required to prepare 250 mL of a 1 M NaOH solution. 2). The mass of potassium hydrogen phthalate (KHP) required to react with 25 mL of a 1 M NaOH solution. The molecular weight of KHP is 204.23 g/mol. 3). The amount of water required to dissolve the quantity of KHP calculated in (b), given that the solubility of KHP is 10.2 grams per liter.
1. Calculate the mass of dried Na2H2EDTA•2H2O needed to prepare exactly 100.00mL of a 0.0100 M...
1. Calculate the mass of dried Na2H2EDTA•2H2O needed to prepare exactly 100.00mL of a 0.0100 M solution. Then, calculate the mass of CoCl2•6H20 required to react completely with 10.0mL of your 0.0100 M EDTAs solution (include 6 molecules of water in molecular weight calculation)