Calculate the volume of 50 % by mass NaOH needed to prepare 1.0L of 0.1 M NaOH solution.
Molarity of the solution = 0.1 M
Volume of solution = 1.0 L
50 % by mass NaOH means:
50 g NaOH present in 100 g of the solution.
500 g NaOH will be present in 1000 g solution.
Molar mass of NaOH = 39.997 g/mole
Moles of NaOH = Mass / Molar mass
= 500 / 39.997
= 12.5 moles
Volume of 1000 g solution = 1 L
Molarity of solution = 12.5 / 1 = 12.5 M
Now,
This NaOH solution is used to prepare 1.0L of 0.1 M NaOH solution.
Let volume V is required to prepare the solution.
M1V1 = M2V2
12.5 * V1 = 1.0 * 0.1
12.5 * V1 = 0.1
V1 = 0.1 / 12.5
V1 = 0.008 L
= 8 mL
Hence,
The volume required is 8 mL
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