Question

Calculate how many milliliters of 1 M NaOH will be needed to make 1 L of 0.1 M solution.

Calculate how many grams of potassium acid phthalate (KHP, FW = 204.2 g/mol) will react with about 25 ml of the 0.1 M NaOH solution. The reaction is as follows:

HKC8H4O4 + NaOH → H2O + NaKC8H4O4

Calculate how many mL of 1 M HCl is needed to make 1 L of 0.2 M HCl.

HCl + NaOH → H2O + NaCl

Answer 1

1) Let M and V be the initial molarity and initial volume and M' and V' be the final molarity and final volume of NaOH solution.

Hence, 100 mL of 1 M NaOH will be required to prepare 1 L of 0.1 M solution

2) As per balanced chemical reaction, 1 mole of KHP will react with 1 mole of NaOH.

Number of moles of NaOH

Number of moles of KHP = 0.0025

Mass of KHP

Hence, 0.51 g of KHP will react with 25 ml of 0.1 M NaOH

3) Let M and V be the initial molarity and initial volume and M' and V' be the final molarity and final volume of HCl solution.

Hence, 200 mL of 1 M HCl will be required to prepare 1 L of 0.1 M solution.